Find the mode of the following data

Explanation

Clearly , the modal class is 60-80 , as it has the maximum frequency
`thereforex_k=60, h=2-0, f_k=12, f_(k-1)=10,f_(k+1)=6`
Mode ` M_o=x_k+{hxx((f_k-f_(k-1)))/(2f_k-f_(k-1)-f_(k+1)}`
`=60+{20xx((12-10))/((2xx12-10-6))}`
`=60+{20xx2/((24-16))}=60+{20xx2/8}=60+5=65` Hence , mode =65