In how many ways can the letters of the expressions `x^(2)y^(3)z^(4)` be arranged when written without using exponents?

Options

A. 1250
B. 1260
C. 1270
D. 1280

Answer

B

Explanation

There are 2 x's, 3y's and 4 z's.
`therefore " total number of arrangements "=(9!)/((2!) xx(3!) xx (4!))`.