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lim(x->1)[(2x-3)(sqrtx-1)]/[2x^2+x-3]...

`lim_(x->1)[(2x-3)(sqrtx-1)]/[2x^2+x-3]`

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`lim_(xto1)((2x-3)(sqrtx-1))/((2x^(2)+x-3))=lim_(xto1)((2x-3)(sqrtx-1))/((2x+3)(x-1))`
`=lim_(xto1)((2x-3)(sqrtx-1)(sqrtx+1))/((2x+3)(x-1)(sqrtx+1))`
`=lim_(xto1)((2x-3)(x-1))/((2x+3)(x-1)(sqrtx+1))`
`=lim_(xto1)((2x-3))/((2x+3)(sqrtx+1))=((2xx11-3))/((2xx1+3)(sqrt1+1))=(-1)/(10).`
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