If O is the origin and OP, OQ are the tangents to the circle `x^(2)+y^(2)+2x+4y+1=0`, the pole of the line PQ is

STATEMENT -1 : if O is the origin and OP and OQ are tangents to the circle x^(2) + y^(2) + 2x + 4y + 1 = 0 the circumcentre of the triangle is ((-1)/(2), -1) . and STATEMENT-2 : OP.OQ = PQ^(2) .

STATEMENT -1 : if O is the origin and OP and OQ are tangents to the circle x^(2) + y^(2) + 2x + 4y + 1 = 0 the circumcentre of the triangle is ((-1)/(2), -1) . and STATEMENT-2 : OP.OQ = PQ^(2) .

If O is the origin and OP, OQ are distinct tangents to the circle x^(2)+y^(2)+2gx+2fy+c=0 then the circumcentre of the triangle OPQ is

If O is the origin and OP, OQ are distinct tangents to the circle x^(2)+y^(2)+2gx+2fy+c=0 then the circumcentre of the triangle OPQ is

If O is the origin OP, OQ are the tangent to the circle x^(2)+y^(2)+2gx+2fy+c=0 then the circumcentre of the triangleOPQ is

If O is the origin and OP and OQ are the tangents from the origin to the circle x^(2)+y^(2)-6x+4y+8-0, then the circumcenter of triangle OPQ is (3,-2) (b) ((3)/(2),-1)((3)/(4),-(1)/(2))( d) (-(3)/(2),1)

If O is the origin and OP,OQ are the tangents from the origin to the circle x^2+y^2-6x+4y=8=0, then circum center of the triangle OPQ is