" If "f(x)={[2+x,,x>=0],[2-x,,x<0];" then "f(f(x))" is given by "

Consider the following in respect of the function f(x)={2+x, x>=0; 2-x, x 1) f(x) does not exist. (2) f(x) is differentiable at x=0 (3) f(x) is continuous at x=0 Which of the above statements is/are correct? (a) 1 only (b) 3 only (c) 2 and 3 only (d) 1 and 3 only

If f(x)={(x^(2))/(|x|),x!=0,0,x=0 then

If f(x)={{:(2+x",", x ge0),(4-x",", x lt 0):}, then f (f(x)) is given by :

If f(x)={{:(2+x",", x ge0),(4-x",", x lt 0):}, then f (f(x)) is given by :

Discuss the continuity of the function f(x), where f(x)= {:{(2-x, x < 0),(2+x,xge0):} , at x = 2,0 and -2.

Which of the following function is not differentiable at x=0?f(x)=min{x,sin x}f(x)={[0,x>=0x^(2),x<0( c) f(x)=x^(2)sgn(x)

If f(x)=2x-|x| , then at x=0

Let f(x)={{:(2^([x]),, x lt0),(2^([-x]),,x ge0):} , then the area bounded by y=f(x) and y=0 is

If f(x) = {{:(x^(2),x le 0),(2 sin x,x gt 0):} , investigate the function at x = 0 for maxima/minima.