A proton `(mass = 1.67xx10^(-27) kg` and charge `1.6xx10^(-19) C)` enters perpendicular to a magentic field of intensity `2 weber//m^(2)` with a speed of `2.6xx10^(7) m//sec`. The acceleration of the proton should be

A proton of mass 1.67 xx 10^(-27) kg and charge 1.6 xx 10^(-19) C is shot a uniform magnetic field, and perpendicular to the field with a velocity 5 xx 10^(6) m//s . If the magnetic induction of the field is 1 tesla, find (i) The radius of the circular path

A proton of mass 1.67 xx 10^(-27) kg and charge 1.6 xx 10^(-19) C is shot a uniform magnetic field, and perpendicular to the field with a velocity 5 xx 10^(6) m//s . If the magnetic induction of the field is 1 tesla, find (i) The radius of the circular path

A proton enters a magnetic fiedl of flux density 1.5"weber"//m^(2) with a velocity of 2xx10^(-7)m//sec at an angle of 30^(@) with the field. The force on the proton will be

A proton has a mass 1.67 xx 10^(-27) kg and charge + 1.6 xx 10^(-19) C. If the proton is accelerated through a potential difference of million volts, then the kinetic energy is

A particle of mass 6.4xx10^(-27) kg and charge 3.2xx10^(-19)C is situated in a uniform electric field of 1.6xx10^5 Vm^(-1) . The velocity of the particle at the end of 2xx10^(-2) m path when it starts from rest is :