The distance of the mid -point of line joining two ponts (4,0) and (0,4) from the centre of the circle `x^(2)+y^(2)=16` is

The distance of the mid point of line joining two points (4, 0) and (0, 4) from the centre of the circle x^(2) + y^(2) = 16 is

The distance of the mid point of the line joining the points (a sin theta, 0)and (0, a cos theta) from the origin is

The distance of the mid point of the line joining the points (a sin theta, 0)and (0, a cos theta) from the origin is

The projection of the line joining the ponts (3,4,5) and (4,6,3) on the line joining the points (-1,2,4) and (1,0,5) is

The projection of the line joining the ponts (3,4,5) and (4,6,3) on the line joining the points (-1,2,4) and (1,0,5) is

If (x,y) be on the line joining the two points (1,-3) and (-4,2), prove that x+y+2=0

If the shortest distance of the parabola y^(2)=4x from the centre of the circle x^(2)+y^(2)-4x-16y+64=0 is "d" ,then d^(2) is equal to:

Find the equation to the locus of mid-points of chords drawn through the point (0, 4) on the circle x^(2) + y^(2) = 16 .

Let P be the point on the parabola y^(2)=4x which is at the shortest distance from the centre S of the circle x^(2)+y^(2)-4x-16y+64=0 . Let Q be the point on the circle dividing the line segment SP internally. Then

Find the distance of the point (1,2) from the mid-point of the line segment joining the points (6,8) and (2,4)