f is a relation on the set R of real numbers defined (a,b) `in f rarr 1 +ab gt0` then f is

Let R be a relation defined on the set of real numbers by aRb iff 1+ab gt 0 then R is

Let a relation R on the set A of real numbers be defined as (a, b) inR implies1+ab >0, AA a, b in A . Show that R is reflexive and symmetric but not transitive.

The relation R, in the set of real number defined as R = {(a,b): a lt b} is:

A relation R_(1) is defined on the set of real numbers as follows: (a,b) in R_(1) hArr 1 + ab gt 0 , when a, b in R (iii) (a,b) in R_(1) and (b,c) in R_(1) rarr (a,c) in R_(1) is not true when a , b, c, in R

S is a relation over the set R^(+) of all real numbers and it is given by (a,b)in S iff ab gt 0 Then S is

The relation R defined on the set of rea Is by (a,b) in R if and only if 1 + ab gt 0 is :

R is the set of real numbers,If f:R rarr R is defined by f(x)=sqrt(x) then f is

Let S be the set of real numbers. Then the relation R={(a, b):1+ab gt 0} on S is -