For the system `A(g)+2B(g) hArr C(g)` the equilibrium concentration is
`A=0.06 mol L^(-1), B=0.12 mol L^(-1)`
`C=0.216 mol L^(-1)` The `K_(eq)` for the reaction is

For the system A (g) + 2 B (g) hArr C(g) the equilibrium concenrations are A =0.06 mol L^(-1) B = 0,12 mol L^(-1) C = 0.216 mol L^(-1) The K_(eq) for the reaction is

For the system A(g)+2B(g)hArr C(g) , the equilibrium concentration is A="0.06 mol L"^(-1), B="0.12 mol L"^(-1), C="0.216 mol L"^(-1) . The equilibrium cosntant K_(C) for the reaction is

In the system X+2YhArrZ , the equilibrium concentration are, [X]=0.06" mol L"^(-1),[Y]=0.12" mol L"^(-1) , [Z]=0.216" mol L"^(-1) . Find the equilibrium constant of the reaction.

In the system X+2YhArrZ , the equilibrium concentration are, [X]=0.06" mol L"^(-1),[Y]=0.12" mol L"^(-1) , [Z]=0.216" mol L"^(-1) . Find the equilibrium constant of the reaction.

In the system X+2Y⇌Z, the equilibrium concentrations are, [X]=0.06 mol L −1 ,[Y]=0.12 mol L −1 ,[Z]=0.216 mol L −1 . Find the equilibrium constant of the reaction.

For a system A+2B hArr 2C the equilibrium concentration are [A]=0.06, [B] = 0.12 and [C]=0.216 The K_c for the reaction is :