चित्र 3 में, AD=4 सेमि, BD=3 सेमि. तथा CB=12 सेमि. हो, तो `cot theta=`

In Fig. if AD = 4cm, BD = 3 cm and CB = 12 cm. then cottheta=

In the figure given below, AD = 4 cm, BD = 3 cm and CB = 12 cm, then cot theta equals:

In triangle ABD , C is the midpoint of BD. If AB = 10 cm, AD = 12 cm and AC = 9 cm, then BD =? त्रिभुज ABD में, C, BD का मध्य बिंदु है | यदि AB = 10 सेमी, AD = 12 सेमी और AC = 9 सेमी है, तो BD = ?

triangle ABC is a triangle, where angle B is obtuse. AD is perpendicular on CB produced at D. If AB = 8cm, BC = 7cm and BD = 4cm, then AC is equal to : ABC एक त्रिभुज है, जिसमें कोण B अधिक कोण है | AD, CB पर लम्ब है जिसे D पर डाला गया है | यदि AB =8 सेमी, BC = 7 सेमी और BD = 4 सेमी है, तो AC किसके बराबर है ?

In the given figure AD = 4 cm BD = 3 cm and CB = 12 cm . Find the value of cot theta

In the given figure, AC = 12 cm, AB = 3 cm and BC = 4 cm. Then cot theta = ?

In Fig.5.48,AD=4cm,BD=3cm and CB=12cm, find cot theta*(12)/(5) (b) (5)/(12) (c) (13)/(12) (d) (12)/(13)( FIGURE)

In triangle ABC , angle ABC=90^@ and BD bot AC . If AD = 4 cm and CD =5 cm, then BD is equal to: त्रिभुज ABC में, angle ABC=90^@ तथा BD bot AC है | यदि AD =4 सेमी और CD = 5सेमी है, तो BD किसके बराबर है ?

In the figure given below, AD=4cm,BD=3cm and CB=12 cm, then cotƟ equals