We can derive different reduction formulas by using integration by parts.
If `int sec^(6)x dx=(1)/(5) tan^(3)x+A tan^(3)x+tanx+c`, then A is equal to-

We can derive different reduction formulas by using integration by parts. If int tan^(6)x dx=(1)/(5) tan^(5)x+A tan^(3)x+tanx+c , then A is equal to-

We can derive different reduction formulas by using integration by parts. If int cosec^(n)x dx=(-cosec^(n-2)x cotx)/(n-1)+A int cosec^(n-2)x dx , then A is equal to-

Method of integration by parts : int tan^(-1)x dx=....

int (sec x)^(m) (tan^(3)x + tan x) dx is equal to

Reduction formulas can be used to compute integrals of higher power of sinx,cosx,tanx etc. intsec^(6)xdx=(1)/(5)tan^(5)x+Atan^(3)x+tanx+C then

Reduction formulas can be used to compute integrals of higher power of sinx,cosx,tanx etc. inttan^(6)xdx=(1)/(5)tan^(5)x+Atan^(3)x+tanx-x+C then

Evaluate the following integrals. int tanx sec^(6) x dx

Evaluate the following integrals. int tanx sec^(6) x dx

int (tanx sec^(2)x)/((1-tan^(2)x))dx.