The specific heat of water `4200 "J kg"^(-1)K^(-1)` and latent heat of ice `=3.4xx10^5 "j kg"^(-1)` . 100 grams of ice at `0^@C` is placed in 200 g of water at `25^@C`. The amount of ice that will melt as the temperature of water reaches `0^@C` is close to (in grams)

One gram of ice at 0^(@)C is added to 5 gram of water at 10^(@)C . If the latent heat of ice be 80 cal/g, then the final temperature of the mixture is -

A piece of ice (heat capacity =2100 J kg^(-1) .^(@)C^(-1) and latent heat =3.36xx10^(5) J kg^(-1) ) of mass m grams is at -5 .^(@)C at atmospheric pressure. It is given 420 J of heat so that the ice starts melting. Finally when the ice . Water mixture is in equilibrium, it is found that 1 gm of ice has melted. Assuming there is no other heat exchange in the process, the value of m in gram is

A piece of ice (heat capacity =2100 J kg^(-1) .^(@)C^(-1) and latent heat =3.36xx10^(5) J kg^(-1) ) of mass m grams is at -5 .^(@)C at atmospheric pressure. It is given 420 J of heat so that the ice starts melting. Finally when the ice . Water mixture is in equilibrium, it is found that 1 gm of ice has melted. Assuming there is no other heat exchange in the process, the value of m in gram is

A piece of ice of mass 100 g and at temperature 0^@ C is put in 200 g of water of 25^@ C . How much ice will melt as the temperature of the water reaches 0^@ C ? (specific heat capacity of water =4200 J kg^(-1) K^(-1) and latent heat of fusion of ice = 3.4 xx 10^(5) J Kg^(-1) ).

A piece of ice of mass 100 g and at temperature 0^@ C is put in 200 g of water of 25^@ C . How much ice will melt as the temperature of the water reaches 0^@ C ? (specific heat capacity of water =4200 J kg^(-1) K^(-1) and latent heat of fusion of ice = 3.4 xx 10^(5) J Kg^(-1) ).

A piece of ice of mass of 100g and at temperature 0^(@)C is put in 200g of water of 25^(@)C .How much ice will melt as the temperature of the water reaches 0^(@)C ? The specific heat capacity of water = 4200 J kg ^(-1)K^(-1) and the specific latent heat of ice = 3.4 xx 10^(5)J kg^(-1)

A piece of ice of mass of 100g and at temperature 0^(@)C is put in 200g of water of 25^(@) How much ice will melt as the temperature of the water reaches 0^(@)C ? The specific heat capacity of water = 4200 J kg ^(-1)K^(-1) and the latent heat of ice = 3.36 xx 10^(5)J kg^(-1)

A piece of ice of mass of 100g and at temperature 0^(@)C is put in 200g of water of 25^(@) How much ice will melt as the temperature of the water reaches 0^(@)C ? The specific heat capacity of water = 4200 J kg ^(-1)K^(-1) and the latent heat of ice = 3.36 xx 10^(5)J kg^(-1)

A piece of ice of mass of 100g and at temperature 0^(@)C is put in 200g of water of 25^(@) How much ice will melt as the temperature of the water reaches 0^(@)C ? The specific heat capacity of water = 4200 J kg ^(-1)K^(-1) and the latent heat of ice = 3.36 xx 10^(5)J kg^(-1)

Calculate the amount of head required to convert 1.00kg of ice at - 10^(@)C into stream at 100^(@)C at normal pressure Specific heat of ice = 2100J kg^(-1)K^(-1) intent heat of fusion of ice = 3.36 xx 10^(5)Jkg^(-1) specific heat capacity of water = 4200 Jkg^(-1)k^(-1) and latent head of vaporisation of water = 2.25 xx 10^(6)J kg^(-1)