[" The area bounded by "y^(2)=4ax" and "y=mx],[" is "(a^(2))/(3)" sq.units then "m=]

The area of the region bounded by the curve y^2= 4 ax and y= mx is (a^2)/(3) Sq. units then the value of m is…………..

" The area bounded by the curve "y=x(x-3)^(2)" and "y=x" is (in sq.units "

Assertion (A) : The area bounded by y^(2)=8x and x^(2)=8y is (64)/(3) sq. units. Reason ( R ) : The area bounded by y^(2)=4ax and x^(2)=4by is (16ab)/(3) sq. units. The correct answer is

Statement 1: The area bounded by parabola y=x^(2)-4x+3 and y=0 is (4)/(3) sq.units. Statement 2: The area bounded by curve y=f(x)>=0 and y=0 between ordinates x=a and x=b (where b>a) is int_(a)^(b)f(x)dx

If the area enclosed by y^(2)=4ax and the line y=ax is (1)/(3) sq.units,then the area enclosed by y=4x with the same curve in sq.units is

Using integration,find the value of m. If the area bounded by parabola y^(2)=16ax and the line y=mx is (a^(2))/(12) square units.

If the area enclosed by y^(2) = 4ax and the line y=ax is (1)/(3) sq. unit, then the roots of the equation x^(2) + 2x = a , are

Show that the area enclosed between y^(2)=4ax and y=mx is (8)/(3)(a^(2))/(m^(3)) sq units.

Show that the area enclosed between y^(2)=4ax and y=mx is (8)/(3)(a^(2))/(m^(3)) sq units.

If the area bounded by the curves y^2 = 4ax and x^2 = 4ay is (16a^2)/3 sq- unit then find the area bounded by y^2 = 2x and x^2 = 2y