The acceleration of block 'C' is equal to `(g)/(12)m//s^(2)` where g is gravitational acceleratio. Acceleration of 'A' is equal to `(10g)/(x)m//s^(2)` then fill the value of x. All surface are smooth and pulleys are light. `(Take g = 10 m//s^(2))`

Find the acceleration of the 6 kg block in the figure. All the surfaces and pulleys are smooth. Also the strings are inextensible and light. [Take g = 10 m//s^(2) ] .

Find the acceleration of the 6 kg block in the figure. All the surfaces and pulleys are smooth. Also the strings are inextensible and light. [Take g = 10 m//s^(2) ] .

Top view of a block on a table is shown (g = 10 m//s^(2)) Find out the acceleration of the block.

What is the value of acceleration due to gravity at a height equal to helf the radius of earth, from surface of earth ? [take g = 10 m//s^(2) on earth's surface]

What is the value of acceleration due to gravity at a height equal to helf the radius of earth, from surface of earth ? [take g = 10 m//s^(2) on earth's surface]

What is the value of acceleration due to gravity at a height equal to half the radius of earth, from surface of earth ? [take g = 10 m//s^(2) on earth's surface]

A wedge (inclination theta = 30^(@) from horizontal) is moving with an acceleration a = 4 m//s^(2) vertically up as shown in figure. What is acceleration of block of mass 1 kg w.r.t & reaction by wedge on block respectively. All surface are smooth. Choose correct pair : (g = 10 m//s^(2))

A wedge (inclination theta = 30^(@) from horizontal) is moving with an acceleration a = 4 m//s^(2) vertically up as shown in figure. What is acceleration of block of mass 1 kg w.r.t & reaction by wedge on block respectively. All surface are smooth. Choose correct pair : (g = 10 m//s^(2))

Calculate the tension in the string shown in figure. The pulley and the string are light and all surfaces are frictionless. Take g=10 m/ s^2 .

Calculate the tension in the string shown in figure. The pulley and the string are light and all surfaces are frictionless. Take g=10 m/ s^2 .