(dy)/(dx)=y tan x-2sin x

The solution of the differential equation (dy)/(dx) = y tan x - 2 sin x , is

If (dy)/(dx)+y tan x=sin2x and y(0)=1, then y(pi) is equal to:

If (dy)/(dx)+y tan x=sin2x and y(0)=1 , then y(pi) is equal to :

Solutions of the differential equations (dy)/(dx) tan y= sin (x+y) +sin (x-y) is

Find the particular solution of the differential equation (dy/dx) + y tan x = sin 2x given that y = 1, x = pi .

(dy) / (dx) tan y = sin (x + y) + sin (xy)

If y=sin x*cos(2x) then prove that (dy)/(dx)=y[cot x-2tan2x]