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[" Question "23" : "],[" In a normal spi...

[" Question "23" : "],[" In a normal spinel type structure,the oxide ions are arranged in ccp whereas "1/8" tetrahedral holes are "],[" occupied by "Zn^(2+)" ions and "50%" of octahedral holes are occupied by "Fe^(3+)" ions.The formula of the compound is "]

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In spinel structure, O^(2-) ions are cubic-closed packed, wherease 1/8th of the tetrahedral holes are occupied by A^(2+) cations and 1/2 of the octahedral holes are occupied by cations B^(3+) . The general formula of this compound is

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In the spinel structur, oxides ions are cubical-closet packed whereas 1/8th of tetrahedral voids are occupied by A^(2+) cation and 1/2 of octahedral voids are occupied by B^(+) cations. The general formula of the compound having spinel structure is: