A particle of charge `q` and velocity v passes undeflected through a space with non-zero electric field E and magnetic field B. The undeflecting conditions will hold, if

A particle of charge q is moving with velocity v in the presence of crossed electric field E and magnetic field B as shown. Write the condition under which the particle will continue moving along x-axis. How would the trajectory of the particle be affected if the electric field is switched off?

A proton (or charged particle) moving with velocity v is acted upon by electric field E and magnetic field B . The proton will move underflected if

Write the expression for the force vecF acting on a particle of charge q moving with a velocity vecv in the prensnece of both electric field vecE and magnetic field vecB . Obtain the condition under which the particle moves undeflected through the fields.

A charged particle with a velocity 2 xx 10^(3) m s^(-1) passes undeflected through electric field and magnetic fields in the mutually perpendicular directions. The magnetic field is 1.5 T. The magnitude of electric field will be

Write the expression for the force vecF , acting on a charged particle of charge q moving with a velocity vecv in the pressure of both electric field vecE and magnetic field vecB . Obtain the condition under which the particle moves undeflected through the fields.

A particle having charge q moves with a velocity v through a region in which both an electric field vecE and a magnetic field B are present. The force on the particle is

A particle having charge q moves with a velocity v through a region in which both an electric field vecE and a magnetic field B are present. The force on the particle is

(a) Write the expression for the force, vecF , acting on a charged particle of charge 'q', moving with a velocity vecV in the presence of both electric field vecE and magnetic field vecB . Obtain the condition under which the particle moves undeflected through the fields. (b) A rectangular loop of size lxxb carrying a steady current I is placed in a uniform magnetic field vecB . Prove that the torque vectau acting on the loop is given by vectau=vecmxxvecB," where "vecm is the magnetic moment of the loop.