" (10) "((3sin x-2)cos x)/(5-cos^(2)x-4sin x)

int(3sin x-2)cos x(dx)/(5-cos^(2)x-4sin x)

Integrate the following w.r. t. x: int frac{(3 sin x- 2) cos x}{5- cos^2 x - 4 sin x} dx

3(sin x + cos x )^(4) + 6(sin x - cos x )^(2) + 4(sin^(6) x + cos^(6) x )=

3-2cos x-4sin x-cos2x+sin2x=0

2cosx-cos3x-cos5x= ............... A) 16 cos ^(3) x sin ^(2) x B) 16 sin^(2) x cos ^(2) x C) 4 cos ^(2) x sin ^(2) x D) 4 sin ^(2) x cos ^(2)x

int(1)/(4sin^(2)x+4sin x cos x+5cos^(2)x)dx

" If "sin^(2)x+sin x cos x-6cos^(2)x=0" and "-(pi)/(2)ltxlt0," then value of "cos2x" is " -3/5 3/5 -4/5 4/5

Show that (sin 8x cos x - sin 6x cos 3x)/(cos 2x cos x - sin 3x sin 4x) = tan 2x

Evaluate: int(sin x cos x)/(3sin^(2)x-4cos^(2)x)dx

3(sin x- cos x )^(4) + 6(sin x+ cos x )^(2) +4 (sin ^(6) x+ cos ^(6) x)=