The force acting on a 4gm mass in the potential field `U= 8x^2 at x= -2 cm` is :

A conservative force acts on a 4 kg particle in x direction. The potential energy U(x) is given by U(X) = 40 + (x – 6)^2 , where x is in metre. If it is given that at x = 8 m, KE is 30 J then find the maximum KE of the particle.

A conservative force acts on a 4 kg particle in x direction. The potential energy U(x) is given by U(X) = 40 + (x – 6)^2 , where x is in metre. If it is given that at x = 8 m, KE is 30 J then find the maximum KE of the particle.

A particle of mass 100 gm moves in a potential well given by U = 8 x^(2) - 4x + 400 joule. Find its acceleration at a distance of 25 cm from equilibrium in the positive direction

A particle of mass 100 gm moves in a potential well given by U = 8 x^(2) - 4x + 400 joule. Find its acceleration at a distance of 25 cm from equilibrium in the positive direction

A particle of mass 4 gm. Lies in a potential field given by V = 200x^(2) + 150 ergs/gm. Deduce the frequency of vibration.

A particle of mass 4 gm. Lies in a potential field given by V = 200x^(2) + 150 ergs/gm. Deduce the frequency of vibration.

The potnetial energy for a force field vecF is given by U(x, y)=cos(x+y) . The force acting on a particle at the position given by coordinates (0, pi//4) is

Figure given below shows the variation of potential energy function U(x), corresponding to a particle lying in a one dimensional force field. The force acting on the particle at x = 2 m is:

The potential energy for a force filed vecF is given by U(x,y)=cos(x+y) . The force acting on a particle at position given by coordinates (0, pi//4) is

The potential energy for a force filed vecF is given by U(x,y)=cos(x+y) . The force acting on a particle at position given by coordinates (0, pi//4) is