The surface tension of water ` = 72 xx10^(-3) jm^(-2)` .The work done in splitting a drop of water of 1 mm radius into 64 droplets is

The work done in splitting a drop of water of 1 mm radius into 10^(6) drops is (S.T. of water =72xx10^(-3)J//m^(2) )

The surface tension of water is 7xx10^(-2) N/m . The work required to break a drop of water of radius 0.5 cm into identical drops , each of radius 1 mm is

The surface tension of water is 7xx10^(-2) N/m . The work required to break a drop of water of radius 0.5 cm into identical drops , each of radius 1 mm is

The work done in splitting a drop of water of 1 mm radius into 64 identical droplets is (S.T. of water is 72xx10^(-3) j//m^2)

If the surface tension of water is 7.3 xx 10^(-2) N/m then the excess pressure inside a spherical drop of water of radius 1 xx 10^(-3) m formed will be

Work done is splitting a drop of water of 1 mm radius into 64 droplets is (surface tension of water =72xx10^(-3)j m^(2))

Work done in splitting a drop of water of 1 mm radius into 10^6 droplets is (Surface tension of water= 72xx10^(-3)J//m^(2) )