The shortest distance between the lines `(x-1)/(0)=(y+1)/(-1)=(z)/(1) and x+y+z+1=0, 2x-y+z+3=0` is :

If the shortest distance between the lines (x-1)/(alpha)=(y+1)/(-1)=(z)/(1) and x+y+z+1=0=2x-y+z+3 is (1)/(sqrt(3)) then value of alpha

Find the shortest distance between the lines,(x-1)/(2)=(y-3)/(4)=(x+2)/(1) and 3x-y-2z+4=0=2x+y+z

Equation of the line of the shortest distance between the lines (x)/(1)=(y)/(-1)=(z)/(1) and (x-1)/(0)=(y+1)/(-2)=(z)/(1) is:

Find the shortest distance between the lines , (x-1)/2=(y-3)/4=(z+2)/1 and 3x-y-2z+4=0=2x+y+z+1 .

The distance between the line (x-2)/(1)=(y-3)/(1)=(z-4)/(5) and the plane 2x+3y-z+5=0 is

Find the distance between the line (x+1)/(-3)=(y-3)/(2)=(z-2)/(1) and the plane x+y+z+3=0

Find the distance between the line (x+1)/(-3)=(y-3)/(2)=(z-2)/(1) and the plane x+y+z+3=0 .

The shortest distance between the line (x-1)/(2)=(y+1)/(3)=(z)/(1) and the line (x+1)/(1)=(y+4)/(1)=(z+1)/(1) is

The shortest distance between the lines (x)/(m_(1))=(y)/(1)=(z-a)/(0) and (x)/(m_(2))=(y)/(1)=(z+a)/(0)