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int(0)^(pi//2)log(tanx+cotx)dx=pi(log2)...

`int_(0)^(pi//2)log(tanx+cotx)dx=pi(log2)`

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int_0^(pi//2)log(tanx)dx

int_(0)^(pi//2)log(tanx)dx=

int_(0)^(pi//2) log (cotx ) dx=

int_(0)^(pi//2) log (cotx ) dx=

Prove that: int_0^(pi//2)log|tanx+cotx|dx=pi(log)_e2

int_0^(pi/2) log|tanx+cotx|dx =

int_(0)^((pi)/(2))log(tanx)dx=0

int_(0)^(pi//2)(cotx)/(tanx+cotx)dx=

int_(0)^((pi)/(2))log(tanx)dx

int_(0)^(pi//4)log(1+tanx)dx=