" 10."4(x+y)(3a-b)+6(x+y)(2b-3a)

Factorize each of the following algebraic expressions: x^(3)(a-2b)+x^(2)(a-2b)2x-3y)(a+b)+(3x-2y)(a+b)4(x+y)(3a-b)+6(x+y)(2b-3a)

Factorize each of the following algebraic expressions: (i) x^3(a-2b)+x^2(a-2b) (ii)2x-3y)(a+b)+(3x-2y)(a+b) (iii)4\ (x+y)(3a-b)+6(x+y)(2b-3a)

Factorize by suitable grouping: 4(a+b)(3x-y)+6(a+b)(2y-3x)

Factorize: (a) (y-x)a+(x-y)b (b) 9(a-2b)^2+6(2b-a) (c) (x-2y)^2-4x+8y (d) 2a+6b-3(a+3b)^2

Factorize each of the following algebraic expressions: (1) (x-y)^2+(x-y) (2) 6(a+2b)-4(a+2b)^2 (3) a(x-y)+2b(y-x)+c(x-y)^2 (4) -4\ (x-2y)^2+8(x-2y)

Factorize each of the following algebraic expressions: 6x(2x-y)7y(2x-y)2r(y-x)+s(x-y)7a(2x-3)+3b(2x-3)9a(6a-5b)-12a^(2)(6a-5b)

Factorize: (y-x)a+(x-y)b9(z-2b)^(2)+6(2b-a)(x-2y)^(2)-4x+8y2a+6b-3(a+3b)^(2)

If (a)/(x-1) + (4b)/(y-2b) + (9c)/(z-3c)= 6-a find (ax)/(x-1) + (2y)/(y-2b) + (3z)/(z-3c) = ?

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))