A point P on the ellipse `(x^2)/(25)+(y^2)/(9)=1` has the eccentric angle `(pi)/(8)`. The sum of the distances of P from the two foci is d. Then `(d)/(2)` is equal to:

The points on the ellipse (x^(2))/(25)+(y^(2))/(9)=1 Whose eccentric angles differ by a right angle are

The dist. of a point P on the ellipse (x^(2))/(12)+(y^(2))/(4)=1 from centre is sqrt(6) then the eccentric angle of Pis

P and Q are two points on the ellipse (x^(2))/(a^(2)) +(y^(2))/(b^(2)) =1 whose eccentric angles are differ by 90^(@) , then

P and Q are two points on the ellipse (x^(2))/(a^(2)) +(y^(2))/(b^(2)) =1 whose eccentric angles are differ by 90^(@) , then

P and Q are two points on the ellipse (x^(2))/(a^(2)) +(y^(2))/(b^(2)) =1 whose eccentric angles are differ by 90^(@) , then

The distance of a point on the ellipse (x^(2))/(6)+(y^(2))/(2)=1 from the centre is 2 Then the eccentric angle of the point is

The distance of a point on the ellipse (x^2)/6+(y^2)/2=1 from the center is 2. Then the eccentric angle of the point is

If P is a point on the ellipse (x^(2))/(36)+(y^(2))/(9)=1 , S and S ’ are the foci of the ellipse then find SP + S^1P

The is a point P on the hyperbola (x^(2))/(16)-(y^(2))/(9)=1 such that its distance from the right directrix is the average of its distance from the two foci. Then the x-coordinate of P is (a) -64/5 (b) -32/9 (c) -64/9 (d)none of these

The distance of a point on the ellipse x^(2)//6+y^(2)//2=1 from the centre is 2. The eccentric angle of the point is