If `theta_1,theta_2,theta_3, ,theta_n` are in AP, whose common difference is `d` , show that `sectheta_1s e ctheta_2+s e ctheta_2sectheta_3+....+sectheta_(n-1)sectheta_n=(t a ntheta_n-t a ntheta_1)/(sind)`

If theta_1,theta_2,theta_3, ,theta_n are in AP, whose common difference is d , show that sectheta_1s e ctheta_2+s e ctheta_2sectheta_3++sectheta_(n-1)sectheta_n=(tantheta_n-tantheta_1)/(sind)

If theta_(1),theta_(2),theta_(2), theta_(3),"…………" Theta_(n) are in AP whose common difference is d, show that sec theta_(1) sec theta_(2)+ sec_(3) +" …" + sec theta _(n-1)sec theta_(n)=(tantheta_(n)-tan theta_(1))/(sin d )

If theta_(1),theta_(2),theta_(2), theta_(3),"…………" Theta_(n) are in AP whose common difference is d, show that sec theta_(1) sec theta_(2)+ sec_(3) +" …" + sec theta _(n-1)sec theta_(n)=(tantheta_(n)-tan theta_(1))/(sin d )

If theta_(1),theta_(2),theta_(3),".......",theta_(n) are in AP whose common difference is d, then show that sind{sectheta_(1) sectheta_(2)+ sectheta_(2)sectheta_(3)+"........"+sectheta_(n-1)sectheta_(n)}=tantheta_(n)-tantheta_(1) .

If theta_(1),theta_(2),theta_(3),".......",theta_(n) are in AP whose common difference is d, then show that sind{sectheta_(1) sectheta_(2)+ sectheta_(2)sectheta_(3)+"........"+sectheta_(n-1)sectheta_(n)}=tantheta_(n)-tantheta_(1) .

sqrt(sec^2theta-1)/(sectheta)

If cos e ctheta-sin theta=m and sectheta-cos theta=n eliminate theta

Prove that: sectheta sec 2theta+sec2thetasec3theta+sec3theta.sec4theta+…to n terms = 1/(sintheta) [tan(n+1)theta-tantheta]