" 26."(dy)/(dx)+2y tan x=sin x,y=0," जब "x=(pi)/(3)

(dy)/(dx) + 2 y tan x = sin x

Solve each of the following initial value problem: (dy)/(dx)=2y tan x=sin x;y=0 when x=(pi)/(3)

(dy)/(dx) + 2 y tan x = sin x, y = 0 when x = (pi)/(3) .

sin2x(dy)/(dx)-y=tan x

Find particular solution of differential equation (dy)/( dx) + 2y tan x = sin x , y =0 , when x = (pi)/(3) .

If y=yır) is the solution of the differential equation, (dy)/(dx) + 2 y tan x = sin x, y ((pi)/(3))= 0, then the maximum value of the function y(x) over R is equal to :

(dy) / (dx) + 2tan x * y = sin x

Solve the differential equation dy/dx+2y tan x=sin x,y=0 when x=pi/3

dy/dx + 2y tan x = sinx, give y = 0 when x= pi/3