(x-y)(dy)/(dx)=(x+2y)

(x-y+1)(dy)/(dx)=x-y+2 , where x-y=u

Solve the following initial value problem: x y(dy)/(dx)=(x+2)(y+2),\ y(1)=-1

For the differential equation x y(dy)/(dx)=(x+2)(y+2) , find the solution curve passing through the point (1, -1) .

For the differential equation x y(dy)/(dx)=(x+2)(y+2) , find the solution curve passing through the point (1, 1) .

The solution of differential equation x^2=1 +(x/y)^(-1)(dy)/(dx)+((x/y)^-2((dy)/(dx))^2)/(2!)+((x/y)^(-3)((dy)/(dx))^3)/(3!)+... i s

The solution of differential equation x^2=1 +(x/y)^(-1)(dy)/(dx)+((x/y)^-2((dy)/(dx))^2)/(2!)+((x/y)^(-3)((dy)/(dx))^3)/(3!)+... i s

x^(2)(dy)/(dx)=(y(x+y))/(2)

The solution of the differential equation (2x-4y+3)(dy)/(dx)+(x-2y+1)=0 is

The solution of the differential equation (2x-4y+3)(dy)/(dx)+(x-2y+1)=0 is