If A, B, C are vertices of a triangle whose position vectors are `vec a, vec b and vec c` respectively and G is the centroid of `Delta ABC, " then " vec(GA) + vec(GB) + vec(GC),` is

If A,B and C are the vertices of a triangle with position vectors vec(a) , vec(b) and vec(c ) respectively and G is the centroid of Delta ABC , then vec( GA) + vec( GB ) + vec( GC ) is equal to

If A,B and C are the vertices of a triangle with position vectors vec(a) , vec(b) and vec(c ) respectively and G is the centroid of Delta ABC , then vec( GA) + vec( GB ) + vec( GC ) is equal to

If G is the centroid of Delta ABC then vec(G)A + vec(G)B + vec(G)C =

If A, B, C are the vertices of a triangle whose position vectors are vec a, vec b, vec c and G is the centroid of the triangle ABC, then vec GA + vec GB + vec GC =

If A, B, C are the vertices of a triangle whose position vectros are vec a,vec b, vec c and G is the centroid of the DeltaABC, then overline(GA)+overline(GB)+overline(GC) =

If A, B, C are the vertices of a triangle whose position vectros are vec a,vec b, vec c and G is the centroid of the DeltaABC, then overline(GA)+overline(GB)+overline(GC) =

If A, B, C are the vertices of a triangle whose position vectros are vec a,vec b, vec c and G is the centroid of the DeltaABC, then overline(GA)+overline(GB)+overline(GC) =

If G is centroid of the triangle ABC, then find vec(GA)+vec(GB)+vec(GC).

If G is the centroid of a triangle ABC, prove that vec(GA)+vec(GB)+vec(GC) = 0

G is the centroid of a triangle ABC, show that : vec(GA)+vec(GB)+vec(GC)=vec0 .