If, from mean value theorem ,
`f'(x_(1))=(f(b)-f(a))/(b-a), ` then:

If from Largrange's mean value theorem, we have f'(x(1))=(f'(b)-f(a))/(b-a) then,

If from Largrange's mean value theorem, we have f(x'(1))=(f'(b)-f(a))/(b-a) then,

In LMV theorem, we have f'(x_(1))=(f(b)-f(a))/(b-a)" then "altx_(1) _________

From mean value theorem, f(b)-f(a) = (b-a)f^(1)(x_(1)), a lt x_(1) lt b if f(x) = ( 1)/( x) then x_(1) =

Using Largrange's mean value theorem f(b)-f(a)=(b-a)f'(c ) find the value of c, given f(x)=x(x-1)(x-2), a=0 and b=(1)/(2) .

Lagrange's mean value theorem is , f(b)-f(a)=(b-a)f'(c ), a lt c lt b if f(x)=sqrt(x) and a=4, b=9, find c.

Lagrange's mean value theorem is , f(b)-f(a)=(b-a)f'(c ), a lt c lt b if f(x)=Ax^(2)+Bx+c" in " a le x le b , find c.

In the mean value theorem, f(b) - f(a) = (b-a) f(c ) , if a= 4, b = 9 and f(x) = sqrt(x) then the value of c is

The mean value theorem is f(b) - f(a) = (b-a) f'( c) . Then for the function x^(2) - 2x + 3 , in [1,3/2] , the value of c: