`tan 5x.tan3x.tan2x=`

tan 5x.tan3x.tan 2x =

tan5x.tan3x*tan2x =

tan x+tan2x+tan3x=0

Statement I: If (1+tan A)(1+tan B)=2 then A+B=45^(@) or 225^(@) Statement II :tan5x+tan3x+tan2x=tan5x tan3x tan2x

Show that tan5x - tan3x - tan2x = tan5xtan3xtan2x

Show that: tan5x-tan3x-tan2x=tan5xtan3xtan2x

STATEMENT-1 : int tan5xtan3xtan2xdx is equal to (log|sec5x|)/(5)-(log|sec3x|)/(3)-(log|sec2x|)/(2)+c and STATEMENT-2: tan5x-tan3x-tan2x=tan5xtan3xtan2x .

STATEMENT-1 : int tan5xtan3xtan2xdx is equal to (log|sec5x|)/(5)-(log|sec3x|)/(3)-(log|sec2x|)/(2)+c and STATEMENT-2: tan5x-tan3x-tan2x=tan5xtan3xtan2x .

tan3x-tan2x-tan x=tan3x tan2x tan x

Show that tan3x tan2x tan x=tan3x-tan2x-tan x