ABC is an isosceles triangle with AB =AC and BD,CE are its two medians. Show that BD=CE .

ABC is an isosceles triangle AB=AC and BD and CE are its two medians. Show that BD=CE.

In Figure,ABC is an isosceles triangle with AB=AC,BD and CE are two medians of the triangle.Prove that BD=CE

ABC is an isosceles triangle with AB = AC and D is a point on AC such that BC^2=ACxxCD . Prove that BD = BC

ABC is an isosceles triangle with AB=AC and D is a pooint on AC such that BC^(2)=ACxCD .Prove that BD=BC

ABC is an isosceles triangle with AB = AC and AD is one of its altitudes. Is BD = CD? Why or why not?

In the given figure, /_\ ABC is an isosceles triangle in which AB - AC. If AB and AC are produced to D and E respectively such that BD = CE, prove that BE = CD. Hint. Show that /_\ ACD = /_\ ABE .

DeltaABC is an isosceles triangle. AB = AC and BD is perpendicular on AC from vertex B, then BD^(2)-CD^(2) is equal to-

In an isosceles triangle ABC, AB = AC and D is a point on BC produced. Prove that : AD^(2)=AC^(2)+BD.CD

ABC is an isosceles triangle in which altitudes BD and CE are drawn to equal sides AC and AB respectively (see figure) Show that these altitudes are equal.

ABC is an isosceles triangle in which altitudes BD and CE are drawn to equal sides AC and AB respectively (see figure) Show that these altitudes are equal.