The frequency of vibration of string is given by `v = (p)/(2 l) [(F)/(m)]^(1//2)`. Here `p` is number of segment is the string and `l` is the length. The dimension formula for `m` will be

The frequency of vibration of string is given by v=p/(2l)[F/m]^(1//2) . Here p is number of segments in the string and l is the length. The dimensional formula for m will be

The frequency of vibration of string is given by v=p/(2l)[F/m]^(1//2) . Here p is number of segments in the string and l is the length. The dimensional formula for m will be

The frequency (n) of vibration of a string is given as n = (1)/( 2 l) sqrt((T)/(m)) , where T is tension and l is the length of vibrating string , then the dimensional formula for m is

The frequency (n) of vibration of a string is given as n = (1)/( 2 l) sqrt((T)/(m)) , where T is tension and l is the length of vibrating string , then the dimensional formula is

The frequency (n) of vibration of a string is given as n=(1)/(2l)sqrt(T/(m)), where T is tension and l is the length of vibrating string, then the dimensional formula for m is :

The mass suspended from the stretched string of a sonometer is 4 kg and the linear mass density of string 4 xx 10^(-3) kg m^(-1) . If the length of the vibrating string is 100 cm , arrange the following steps in a sequential order to find the frequency of the tuning fork used for the experiment . (A) The fundamental frequency of the vibratinng string is , n = (1)/(2l) sqrt((T)/(m)) . (B) Get the value of length of the string (l) , and linear mass density (m) of the string from the data in the problem . (C) Calculate the tension in the string using , T = mg . (D) Substitute the appropriate values in n = (1)/(2l) sqrt((T)/(m)) and find the value of 'n' .

The frequency of vibration of string depends on the length L between the nodes, the tension F in the string and its mass per unit length m. Guess the expression for its frequency from dimensional analysis.