`25^(@)C` ताप पर
`Ag+I^(-) to AgI+e^(-), E^(@)=0.152V`
`Ag to Ag^(+), E^(@)=-0.800V`
Agl के लिए `log K_(sp)` का मान कितना होगा? `((2.303RT)/(F)=0.059V)`

Options

A. `-8.12`
B. `-8.612`
C. `-37.83`
D. `-16.13`

Answer

D

Explanation

`AgI(s)+e^(-) Leftrightarrow Ag(s)+I^(-) , E^(@)=-0.152V`
`Ag(s) to Ag^(+) +e^(-) E^(@)=-0.8V`
`AgI(s) to Ag^(+)+I^(-), E^(@)=-0.952V`
`E_("सेल")=(0.059)/(n) log K_(sp)`
`-0.952=(0.59)/(1) log K_(sp)`
`log K_(sp)=(0.952)/(0.059)=-16.135`