Let f(x) and g(x) be two equal real function such that `f(x)=(x)/(|x|) g(x), x ne 0`
If g(0)=g'(0)=0 and f(x) is continuous at x=0, then f'(0) is

Given that f(x) = xg (x)//|x| g(0) = g'(0)=0 and f(x) is continuous at x=0 then the value of f'(0)

Let f(x) = (x+|x|)/x for x ne 0 and let f (0) = 0, Is f continuous at 0?

Let f (x), g(x) be two real valued functions then the function h(x) =2 max {f(x)-g(x), 0} is equal to :

Let f (x), g(x) be two real valued functions then the function h(x) =2 max {f(x)-g(x), 0} is equal to :

Let f(x) and g(x) be differentiable functions such that f'(x)g(x)!=f(x)g'(x) for any real x. Show that between any two real solution of f(x)=0, there is at least one real solution of g(x)=0.

Let f(x) be a polynomial of degree one and f(x) be a function defined by f(x)={(g(x), x le0), ((1+x)/(2+x)^(1//x), x gt0):} If f(x) is continuous at x=0 and f(-1)=f'(1), then g(x) is equal to :

Let f(x) be a real valued function such that f(a)=0. If g(x)=(x-a)f(x) is continuous but notdifferentiable at x=a and h(x)=(x-a)^(2)f(x) is continuous and differentiable at x=a .Then f(x)