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AAKASH SERIES-BINOMIAL THEOREM-PRACTICE EXERCISE
- If three successive coefficients in (1+x)^n are 6,15,20 then n =
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- If a1,a2,a3,a4 are the coefficients of 2nd, 3rd, 4th and 5th terms of ...
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- If a,b,c,d are conseentive binomial coefficients of (1+x)^n then (a+b)...
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- Coefficient of x^5 in (1+x +x^2 +x^3)^10 is
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- The coefficient of x^4 in the expansion of (1+x-2x^2)^7 is
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- Binomial coefficients which are in decreasing order are
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- Coefficient of x^3 in 1+(1+x) +(1 +x)^2 +…..+(1+x)^n is
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- Sum of the coefficients of (1+2x-4x^2)^(2003)
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- Sum of coefficients of terms of even powers of x in (1 + x + x^2 + x^...
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- Sum of coefficients of terms of odd powers of in (1+x - x^2 -x^3)^8is
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- If (1+x -2x^2)^8 =1 -a1x + a2x^2+……+a16x^16, then a2+a4+a6+……+a16 =
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- If (1+x-2x^2)^8 = 1 + a1x + a2x^2 + ……+ a16 x^16, then a1 +a3 + a5 + …...
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- (1+x)^25 = sum(r = 0)^(25) Cr x^r then C1 - C3 + C5 - C7 + ……-C25 =
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- The sum of the coefficients in the expansion of (1+x-3x^2)^(171) is
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- If the sum of all the binomial coefficients in (x+y)^n is 512 , then t...
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- The coefficient of x^(-n) in (1+x)^n (1+(1)/(x))^n is
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- If n is a positive integer then 2^(4n) - 15n - 1 is divisible by
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- Smaller of (19^10 + 20^10) and 21^10 is
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- 9^11 + 11^9 is divisible by
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- Integral part of (8 + 3sqrt7)^n is
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