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A circle of radius r is concentric with ...

A circle of radius r is concentric with the ellipse `(x^(2))/(a^(2))+(y^(2))/(b^(2)) = 1` Prove that slope of the common tangent of the above curves is `sqrt((r^(2)-b^(2))/(a^(2)-r^(2)))`

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The correct Answer is:
`sqrt(r^(2)-b^(2))/(a^(2)-r^(2))`
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