Home
Class 12
MATHS
Find the equation of normal to the ellip...

Find the equation of normal to the ellipse `(x^(2))/(16)+(y^(2))/(9)` = 1 at the point whose eccentric angle `theta=(pi)/(6)`

Text Solution

Verified by Experts

The correct Answer is:
`7sqrt(3)`
Promotional Banner

Topper's Solved these Questions

  • ELLIPSE

    AAKASH SERIES|Exercise ADDITIONAL EXERCISE|34 Videos

  • ELLIPSE

    AAKASH SERIES|Exercise EXERCISE-I|52 Videos

  • ELLIPSE

    AAKASH SERIES|Exercise EXERCISE 4.2 (SHORT ANSWER QUESTIONS)|7 Videos

  • DIFFERENTIAL EQUATIONS

    AAKASH SERIES|Exercise Practice Exercise|62 Videos

  • EXPONENTIAL SERIES

    AAKASH SERIES|Exercise EXERCISE - III|8 Videos

Similar Questions

Explore conceptually related problems

The equation of the normal to the ellipse x^(2)//16+y^(2)//9=1 at the point whose eccentric angle theta=pi//6 is

The equation of the normal to the ellipse (x^(2))/(4)+(y^(2))/(2)=1 at the point whose eccentric angle is (pi)/(4) is

Find the equations of tangent and normal to the ellipse 2x^2+3y^2=11 at the point whose ordinate is 1.

The equation of the normal to the hyperbola (x^(2))/(25) -(y^(2))/(9) =1 at the point theta = (pi)/(4) is

The eccentricity of the ellipse (x^(2))/(16)+(y^(2))/(25) =1 is

Find the equation of tangent and normal to the ellipse x^2+8y^2=33 at (-1,2).

(i) Find the equations of the tangent and normal at the positive end of the latusrectum of the ellipse 9x^(2) + 1 6 y^(2) = 144 (ii) Find the equations of the tangent and normal to the ellipse 2x^(2) + 3y^(2) = 11 at the point whose ordinate is one.

The eccentricity of the ellipse (x-1)^(2)/(16)+(y-2)^(2)/(9)=1 is