An X-ray beam `(lambda = 70.9 p m)` was scattered by a crystalline solid. The angle `(2theta)` of the diffraction for a second order reflection is `14.66^(0)`. Calculate the distance between parallel planes of atoms of the crystalline solid.

Explanation

The Bragg.s equation is given as,
`n lambda=2d sin theta`
n = order of reflection = 2
`lambda =` wave length of X-rays `= 7.09 xx 10^(-11)m`
`theta = ` Angle of reflection `= 7.33^(0)`
d = distance between parallel planes Distance between parallel planes `(d) = (lambda)/(sin theta)=(7.099xx10^(-11))/(sin 7.33^(0))d=6.18xx10^(-10)m`