S(2) molecule in vapour state is paramag...

`S_(2)` molecule in vapour state is paramagnetic due to the presence of unpaired electrons is

Bonding boiling `sigma` orbitals

Anti bonding `sigma^(**)` orbtials

Anti bonding `pi^(**)` orbitals

Bonding `pi` orbitals

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

VIA GROUP ELEMENTS
AAKASH SERIES|Exercise OBJECTIVE EXERCISE - 1 (HYDRIDES)|11 Videos
VIA GROUP ELEMENTS
AAKASH SERIES|Exercise OBJECTIVE EXERCISE - 1 (HALIDES AND OXIDES)|19 Videos
VIA GROUP ELEMENTS
AAKASH SERIES|Exercise SUBJECTIVE EXERCISE - 3(VERY SHORT ANSWER QUESTIONS)|3 Videos
VA GROUP ELEMENTS
AAKASH SERIES|Exercise PRACTICE EXERCISE|51 Videos
VII GROUP ELEMENTS
AAKASH SERIES|Exercise OBJECTIVE EXERCISE -4|55 Videos

Similar Questions

Explore conceptually related problems

The paramagnetic character of transition metals is due to the presence of unpaired electron in

(A) In vapour state S_(2) molecule is paramagnetic like O_(2) (R ) S_(2) molecule in vapour state contains two unpaired electrons in bonding molecular orbitals

(A) Ionic solids conduct electricity in solid state. (R) Their conduction is due to the presence of electrons

Nickel combines with a uninegative monodentate ligand X to form a paramagnetic complex [NiX_4]^(2-) . The number of unpaired electron/s in the nickel and geometry of this complex ion are respectively

The magnetic nature of elements depends on the presence of unpaired electrons. Identify the configuration of transition elements which shows highest magnetic moment ?

(A) Potassium ferrocyanide and potassium ferricyanide both are paramagnetic. (R) Both have unpaired electrons

Valence bond theory successfully explains the magnetic behaviour of complexes. The substances which contains unpaired electrons are paramagnetic and paramagnetic character increases as the number of unpaired electrons increases. Magnetic moment of a complex can be determined experimentally and by using formula sqrt(n(n+2)) and we can determine the number of unpaired electrons in it. This information is important in writing electronic structure of complex which in turn also useful in deciding the geometry of complex. Which of the following are diamagnetic ? 1) K_(4)[Fe(CN)_(6)] 2) K_(3)[Cr(CN)_(6)] 3) K_(3)[Co(CN)_(6)] 4) K_(2)[Ni(CN)_(4)]

AAKASH SERIES-VIA GROUP ELEMENTS-OBJECTIVE EXERCISE - 1 (GENERAL CHARACTERISTICS)

Element with the lowest atomicity
Text Solution
|
The number of atoms present in one molecule of rhombic sulphur is
Text Solution
|
The total number of covalent bonds present in one S(8) molecule is
Text Solution
|
The S - S - S bond angle in S(8) molecule is
Text Solution
|
The decreasing tendency to exist in puckered 8 - membered ring structu...
Text Solution
|
S(2) molecule in vapour state is paramagnetic due to the presence of u...
Text Solution
|
alpha, beta and gamma forms of sulphur differ in
Text Solution
|
The oxidation state of oxygen is zero in
Text Solution
|
In which of the following compounds, oxygen exhibits +2 oxidation stat...
Text Solution
|
Which of the following element does not show an oxidation state of +4 ...
Text Solution
|
Generally oxygen is converted into its ion by
Text Solution
|
If X is a member of chalcogen family, the highest stability of X^(-2) ...
Text Solution
|
Oxygen is always divalent while sulphur can form 2, 4 and 6 bonds beca...
Text Solution
|
In sulphate ion the oxidation state of sulphur is +6 and the hybridiza...
Text Solution
|
The second most electronegative element in periodic table is
Text Solution
|
Which of the following has higher IP ?
Text Solution
|
Element with higher catenation capacity is
Text Solution
|
The order of electron gain enthalpy of VI A group elements is
Text Solution
|
The most common oxidation state of VI A group elements is
Text Solution
|
Chair form of S(6) rings are present in
Text Solution
|