The equivalent mass of K(2)Cr(2)O(7) whe...

The equivalent mass of `K_(2)Cr_(2)O_(7)` when it acts as oxidising agent in acidic medium, is equal to

M/3

M/2

M/6

M/5

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(A): Equivalent mass of K_(2)Cr_(2)O_(7) , when it acts as oxidizing agent in acidic medium, is M/3 (R) : During reduction, oxidation number of chromium changes from +6 to +3

Equivalent weights of K_(2)Cr_(2)O_(7) in acidic medium is

The equivalent weights of oxidising and reducing agents can be calculated by the number of electrons gained or lost. The equivalent weight of an oxidising agent is the number of parts by weight of the substance which gains one electron. Thus, it is equal to the molecular weight of the substance divided by the number of electrons gained in the balanced chemical equation. Similarly, equivalent weight of a reducing agent is equal to the molecular weight divided by the number of electrons lost as represented in the balanced chemical equation The equivalent weight of barium in BaCrO_4 used as an oxidising agent in acidic medium is (At, wt, of Ba - 137.34)

Equivalent weight of K_(2)Cr_(2)O_(7) as oxidant in acidic medium is

(A) Equivalent mass of KMnO_4 is equal to one-third of its molecular mass when it acts as an oxidising agent in faint alkaline medium (R) Oxidation number of Mn is +7 KMnO_4

The atomicity of K_2Cr_2O_7 is

In which of the following reactions, H_(2)O_(2) acts as oxidising agent ?

Acidified K_(2)Cr_(2)O_(7) turns green by

Why does O_(3) act as a powerful oxidising agent ?

AAKASH SERIES-D - BLOCK ELEMENTS-PRACTICE EXERCISE

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