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If |z1|+|z2|=1a n dz1+z2+z3=0 then the a...

If `|z_1|+|z_2|=1a n dz_1+z_2+z_3=0` then the area of the triangle whose vertices are `z_1, z_2, z_3` is `3sqrt(3)//4` b. `sqrt(3)//4` c. `1` d. `2`

A

`3 sqrt(3)//4`

B

`sqrt(3)//4`

C

1

D

2

Text Solution

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The correct Answer is:
A
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Knowledge Check

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