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Let z be a complex number such that |z| ...

Let z be a complex number such that |z| = 2, then maximum possible value of `|z + (2)/(z)|` is

A

1

B

2

C

3

D

4

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The correct Answer is:
To solve the problem, we need to find the maximum possible value of the expression \( |z + \frac{2}{z}| \) given that \( |z| = 2 \). ### Step-by-step Solution: 1. **Understanding the Given Information**: We know that \( z \) is a complex number such that \( |z| = 2 \). This means that \( z \) lies on a circle of radius 2 in the complex plane. 2. **Rewriting the Expression**: We want to maximize the expression \( |z + \frac{2}{z}| \). We can rewrite \( \frac{2}{z} \) using the property of modulus: \[ \left| \frac{2}{z} \right| = \frac{2}{|z|} = \frac{2}{2} = 1 \] Therefore, we can express the original expression as: \[ |z + \frac{2}{z}| = |z + w| \] where \( w = \frac{2}{z} \) and \( |w| = 1 \). 3. **Using the Triangle Inequality**: By the triangle inequality, we have: \[ |z + w| \leq |z| + |w| \] Substituting the values we know: \[ |z + w| \leq |z| + |w| = 2 + 1 = 3 \] 4. **Finding the Maximum Value**: To check if the maximum value of 3 can actually be achieved, we need to find \( z \) and \( w \) such that they are in the same direction. This occurs when: \[ z = 2e^{i\theta} \quad \text{and} \quad w = e^{i\theta} \] for some angle \( \theta \). Thus: \[ |z + w| = |2e^{i\theta} + e^{i\theta}| = |(2 + 1)e^{i\theta}| = |3e^{i\theta}| = 3 \] Therefore, the maximum value of \( |z + \frac{2}{z}| \) is indeed 3. 5. **Conclusion**: Hence, the maximum possible value of \( |z + \frac{2}{z}| \) is \( \boxed{3} \).
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