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Equation of a directrix of the ellipse x...

Equation of a directrix of the ellipse `x^2/36+y^2/4=1` is

A

9x-8=0

B

8x-9=0

C

`sqrt2x+9=0`

D

`x+9sqrt2=0`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • The equation of a directrix of the ellipse x^2/16+y^2/25=1 is

    A
    `3y=+-5`
    B
    `y=+-5`
    C
    `3y=+-25`
    D
    `y=+-3`

  • If equation of directrix of an ellipse x^2/a^2+y^2/b^2=1 is x=4, then normal to the ellipse at point (1,beta),(beta gt 0) passes through the point (where eccentricity of the ellipse is 1/2 )

    A
    `(1,3/2)`
    B
    `(-1,3/2)`
    C
    `(-1,-3)`
    D
    `(3,-1)`

  • Equation of a tangent to the ellipse x^2/36+y^2/25=1 , passing through the point where a directrix of the ellipse meets the + ve x-axis is

    A
    `5y+sqrt11x=36`
    B
    `6y+sqrt11x=25`
    C
    `6y+sqrt11x=36`
    D
    `6y-sqrt11x=36`

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