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Let d be the perpendicular distance from...

Let d be the perpendicular distance from the centre of the ellipse `x^2/a^2+y^2/b^2=1` to the tangent drawn at a point P on the ellipse. If `F_1 & F_2` are the two foci of the ellipse, then show the `(PF_1-PF_2)^2=4a^2[1-b^2/d^2]`.

A

`4b^2(1-a^2/d^2)`

B

`4d^2(1-b^2/a^2)`

C

`4a^2(1-b^2/d^2)`

D

`4a^2`

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The correct Answer is:
C
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