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Sets A, B, C, Ann B , AnnC , B nn C and...

Sets A, B, C, `Ann B , AnnC , B nn C` and `AnnB nnC` have 35, 40, 45, 13, 12, 14 and 5 elements respectively. An element is selected at random from the set `AuuBuuC`. The probability that the selected element belongs to only set A is:

A

`13/86`

B

`35/86`

C

`5/86`

D

`15/86`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the probability that a randomly selected element from the set \( A \cup B \cup C \) belongs only to set \( A \). We will follow these steps: ### Step 1: Calculate the total number of elements in \( A \cup B \cup C \) The formula for the total number of elements in the union of three sets is given by: \[ n(A \cup B \cup C) = n(A) + n(B) + n(C) - n(A \cap B) - n(B \cap C) - n(A \cap C) + n(A \cap B \cap C) \] Given values: - \( n(A) = 35 \) - \( n(B) = 40 \) - \( n(C) = 45 \) - \( n(A \cap B) = 13 \) - \( n(B \cap C) = 12 \) - \( n(A \cap C) = 14 \) - \( n(A \cap B \cap C) = 5 \) Substituting these values into the formula: \[ n(A \cup B \cup C) = 35 + 40 + 45 - 13 - 12 - 14 + 5 \] Calculating step-by-step: 1. Sum of individual sets: \( 35 + 40 + 45 = 120 \) 2. Sum of intersections: \( 13 + 12 + 14 = 39 \) 3. Total: \( 120 - 39 + 5 = 86 \) Thus, \[ n(A \cup B \cup C) = 86 \] ### Step 2: Calculate the number of elements that belong only to set \( A \) To find the number of elements that belong only to set \( A \), we use the formula: \[ n(\text{only } A) = n(A) - n(A \cap B) - n(A \cap C) + n(A \cap B \cap C) \] Substituting the known values: \[ n(\text{only } A) = 35 - 13 - 14 + 5 \] Calculating step-by-step: 1. Subtract intersections: \( 35 - 13 - 14 = 8 \) 2. Add the intersection of all three sets: \( 8 + 5 = 13 \) Thus, \[ n(\text{only } A) = 13 \] ### Step 3: Calculate the probability that a randomly selected element belongs only to set \( A \) The probability \( P \) that a randomly selected element belongs only to set \( A \) is given by: \[ P(\text{only } A) = \frac{n(\text{only } A)}{n(A \cup B \cup C)} \] Substituting the values we calculated: \[ P(\text{only } A) = \frac{13}{86} \] ### Final Answer Thus, the probability that the selected element belongs only to set \( A \) is: \[ \frac{13}{86} \] ---
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