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Suppose A and B are two events such that...

Suppose A and B are two events such that P(A) = 0.5 and P(B) = 0.8, then which one of the following is not true?

A

`P(AnnB) le 0.5`

B

`P(AnnB) ge 0.3`

C

`P(A' nn B ) le 0.5`

D

`P(A nn B') le 0.1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the probabilities of events A and B, and determine which of the statements regarding these probabilities is not true. We are given: - \( P(A) = 0.5 \) - \( P(B) = 0.8 \) We will evaluate the statements one by one. ### Step 1: Understand the basic properties of probabilities The probability of the union of two events A and B can be expressed as: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] This means that the probability of either A or B occurring is equal to the sum of their individual probabilities minus the probability of both A and B occurring. ### Step 2: Calculate the maximum possible value of \( P(A \cap B) \) Since the probability of any event cannot exceed 1, we can derive: \[ P(A \cup B) \leq 1 \] Substituting the values we have: \[ P(A) + P(B) - P(A \cap B) \leq 1 \] \[ 0.5 + 0.8 - P(A \cap B) \leq 1 \] \[ 1.3 - P(A \cap B) \leq 1 \] \[ P(A \cap B) \geq 0.3 \] This means that the minimum value of \( P(A \cap B) \) is 0.3. ### Step 3: Calculate the maximum possible value of \( P(A \cap B) \) Since \( P(A) = 0.5 \), the maximum value of \( P(A \cap B) \) cannot exceed \( P(A) \): \[ P(A \cap B) \leq P(A) = 0.5 \] ### Step 4: Analyze the statements Now we will analyze the statements provided in the question: 1. **Statement 1**: \( P(A \cap B) \leq 0.5 \) This is true since \( P(A \cap B) \) cannot exceed \( P(A) \). 2. **Statement 2**: \( P(A \cap B) > 0.3 \) This is not necessarily true since \( P(A \cap B) \) could be exactly 0.3. 3. **Statement 3**: \( P(A^c \cap B) \leq 0.5 \) This is true because \( P(A^c \cap B) = P(B) - P(A \cap B) \) and since \( P(A \cap B) \geq 0.3 \), \( P(A^c \cap B) \) will be less than or equal to 0.5. 4. **Statement 4**: \( P(A \cap B^c) < 0.2 \) This is true since \( P(A \cap B^c) = P(A) - P(A \cap B) \) and since \( P(A \cap B) \) can be at most 0.5, \( P(A \cap B^c) \) can be less than 0.2. ### Conclusion The statement that is not true is **Statement 2**: \( P(A \cap B) > 0.3 \).
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