If `S(p,q,r)=(~p)vv(~(q ^^ r))` is a compound statement, then `S(~p,~q,~r)` is

If (p ^^ ~q) to (~ p vv r) is a false statement, then respective truth values of p, q and r are

If (p ^^ ~q) to (~ p vv r) is a false statement, then respective truth values of p, q and r are

If statement (p vv-r)rarr(q^^r) is false and statement q is true then statement p is-

Let p, q, r be three simple statements. Then, ~(p vv q) vv ~ (p vv r) is equal to a) (~p) ^^ (~q vv ~ r) b) (~p) ^^ (q ^^ r) c) p ^^ (q vv r) d) p vv (q ^^ r)

The dual of the statement (p vv q) ^^ ~(r vv s) is

Observe the following statements I : The dual of [ ~p ^^ q)] vv [ p ^^ {~(q vv ~s)}] is [~(p vv q)] ^^ [p vv{~(q ^^ ~s)}] II : The dual of ~p ^^ [(~q) ^^ (p vv q) ^^ ~r] is ~p vv[~q) vv(p ^^ q) vv ~r] The true statements in the above is/are :

Observe the following statements I : The dual of [ ~p ^^ q)] vv [ p ^^ {~(q vv ~s)}] is [~(p vv q)] ^^ [p vv{~(q ^^ ~s)}] II : The dual of ~p ^^ [(~q) ^^ (p vv q) ^^ ~r] is ~p vv[~q) vv(p ^^ q) vv ~r] The true statements in the above is/are :

The logical statement [~(~pvvq)vv(p^^r)]^^(~q^^r) is equivalent to (a) (~p^^~q)^^r (b) ~p vv r (c) (p^^r)^^~q (d) (p^^~q)vvr