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If 2 kg of steam at 100^(@)C condenses i...

If 2 kg of steam at `100^(@)C` condenses into water at `40^(@)C`, then the enegy evolved in calories will be `(L=540cal//gm,C=1cal//gm.^(@)C)`

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1 gm of ice at 0^@C is converted to steam at 100^@C the amount of heat required will be (L_("steam") = 536 cal//g) .

6 gm of steam at 100^@ C is mixed with 6 gm of ice at 0^@ C . Find the mass of steam left uncondensed. (L_(f)=80 cal//g,L_(v)= 540cal//g, S_(water) = 1cal//g-^(@) C) .

1 g of a steam at 100^(@)C melt how much ice at 0^(@)C ? (Length heat of ice = 80 cal//gm and latent heat of steam = 540 cal//gm )

450 g water at 40^(@)C was kept in a calorimeter of water equivalent 50 g 25 g ice at 0^(@)C is added and simultaneously 5 g steam at 100^(@)C was passed to the calorimeter. The final temperature of the calorimeter. Will be (L_(ice)=80 cal // g.L_(steam) =540cal//g)

5 g of steam at 100^(@)C is mixed with 10 g of ice at 0^(@)C . Choose correct alternative /s) :- (Given s_("water") = 1"cal"//g ^(@)C, L_(F) = 80 cal//g , L_(V) = 540cal//g )

5 g of steam at 100^(@)C is mixed with 10 g of ice at 0^(@)C . Choose correct alternative /s) :- (Given s_("water") = 1"cal"//g ^(@)C, L_(F) = 80 cal//g , L_(V) = 540cal//g )

5 g of steam at 100^(@)C is mixed with 10 g of ice at 0^(@)C . Choose correct alternative /s) :- (Given s_("water") = 1"cal"//g ^(@)C, L_(F) = 80 cal//g , L_(V) = 540cal//g )

If there is no heat loss, the heat released by the condensation of x gram of steam at 100^@C into water at 100^@C can be used to convert y gram of ice at 0^@C into water at 100^@C . Then the ratio of y:x is nearly [Given L_l = 80 cal//gm and L_v= 540 cal//gm ]

If there is no heat loss, the heat released by the condensation of x gram of steam at 100^@C into water at 100^@C can be used to convert y gram of ice at 0^@C into water at 100^@C . Then the ratio of y:x is nearly [Given L_l = 80 cal//gm and L_v= 540 cal//gm ]

When m gram of steam at 100^(@) C is mixed with 200 gm of ice at 0^(@)C . it results in water at 40^(@) C . Find the value of m in gram . (given : Latent heat of fusion ( L_f ) = 80 cal/gm, Latent heat of vaporisation ( L_v ) = 540 cal/gm., specific heat of water ( C_w )= 1 cal/gm/C)