यदि `sin B = 1/2,"तो सिद्ध करें कि " 3 cos B - 4 cos^(3) B = 0`

If sin B = (1)/(2), then 3 cos B - 4 cos ^(3)B is equal to (a) 1 (b) 3/4 (c) 0 (d) 2 (1)/(2)

If sin B = 0.5, find the value of 3 cos B-4cos^(3)B

ig sin B=(1)/(2) then prove that 3cos B-4cos^(3)B=0

In a triangle ABC if sin B=(1)/(2)=cos A then 3cos B-4cos^(3)B=(i)sin C(ii)cos C(iii)0(iv)3(sqrt(3))/(2)

sin 2A + sin 2B + sin 2 (A-B)= A) 4 sin A * sin B * sin (A-B) B) 4 sin A * cos B * cos (A-B) C) 4 cos A * sin B * cos (A-B) D) 4 cos A * cos B * sin (A-B)

sin A + sin B + sin C = cos A + cos B + cos C = 0then (A) cos (AB) = - (1) / (2) (B) sin ^ (2) A + sin ^ (2) B + sin ^ (2) C = 0 (C) sin ^ (2) A + sin ^ (2) B + sin ^ (2) C = (3) / (2) (D) cos ^ (2) A + cos ^ (2) B + cos ^ (2) C = (3) / (2)

If det [[cos (A + B), - sin (A + B), cos2Bsin A, cos A, sin B-cos A, sin A, cos B]] = 0

If det [[cos (A + B), - sin (A + B), cos2Bsin A, cos A, sin B-cos A, sin A, cos B]] = 0

If cos(A+B) = 0 and sin(A-B) = 1/2, then the value of B is: (Given 0^@ यदि cos(A+B) = 0 और sin(A-B) = 1/2, B का मान है: