A body weighs W newton at the surface of the earth. Its weight at a height equal to half the radius of the earth, will be

Statement-1 : A body weight W newton on the surface of the earth. Its weight at a height equal to half the radius of the earth will be 2 W//5 . Statement-2 : g' = g.(R^(2))/((R + h)^(2))

Statement-1 : A body weight W newton on the surface of the earth. Its weight at a height equal to half the radius of the earth will be 2 W//5 . Statement-2 : g' = g.(R^(2))/((R + h)^(2))

Assertion. A body weighs X newton on the surface of the earth. Its weight at a height equal to half the radius of the earth will be (2X)/5 Reason: g^'=g(r^2/(R+h)^2

A body weighs w Newton on the surface of the earth. Its weight at a height equal to half the radius of the earth, will be x/y w where x and y are coprimes . Find x and y

A body weighs w Newton on the surface of the earth. Its weight at a height equal to half the radius of the earth, will be x/y w where x and y are coprimes . Find x and y

A body weighs one Newton at the surface of the earth. What will be it’s weight at a height equal to half the radius of the earth ?

The weight of an object on the surface of the Earth is 40 N. Its weight at a height equal to the radius of the Earth is

The weight of an object on the surface of the Earth is 40 N. Its weight at a height equal to the radius of the Earth is